6p^2+21p=0

Solution for 6p^2+21p=0 equation:

6p^2+21p=0

a = 6; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·6·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*6}=\frac{-42}{12}
=-3+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*6}=\frac{0}{12}
=0
$